Date:2025-11-13 Categories:Product knowledge Hits:260 From:Guangdong Youfeng Microelectronics Co., Ltd
First, halve the length, so the new length is half of the original: [L' = \frac{L}{2}]. Second, double the cross-sectional area, so the new cross-sectional area is twice the original: [A' = 2A]. Substitute these changes into the resistance formula to obtain the new resistance value: [R' = \rho \frac{L'}{A'} = \rho \frac{\frac{L}{2}}{2A} = \rho \frac{L}{4A} = \frac{1}{4}R]. This means the resistance of the folded wire will be one-fourth of the original.diode
This result may not be immediately intuitive, as one might expect that halving the length and doubling the cross-sectional area would leave the resistance unchanged. However, it is crucial to remember that the increase in cross-sectional area has a more significant impact on reducing resistance. The resistivity (ρ) and the properties of the wire material remain constant, so the change in resistance is entirely determined by the alterations in length and cross-sectional area. Consequently, when the wire is folded, its resistance decreases, making it more conductive.diode
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